Actress Kim Shin-rok is garnering significant attention for her compelling performance as Prosecutor Kang Young-ae in the MBC Friday-Saturday drama 'Fifty Percent' (오십프로). Across episodes 3 and 4, which aired on the 29th and 30th, her character deepened the tension by investigating a 10-year-old espionage and murder case alongside Kim Sang-ho. Beyond her screen success, Kim Shin-rok was also honored at the '62nd Baeksang Arts Awards with Gucci' gala dinner, where she received the Acting Award in the theater category. - Kim Shin-rok stars as Prosecutor Kang Young-ae in the MBC drama 'Fifty Percent', which reached a peak viewership rating of 6.1%. - She was officially recognized for her artistic excellence by winning the Acting Award in the theater category at the '62nd Baeksang Arts Awards with Gucci'. Q: Why is this trending? A: Kim Shin-rok is trending due to her dual success in receiving a prestigious acting award at the 62nd Baeksang Arts Awards and her gripping performance in the hit drama 'Fifty Percent'. | Actress Kim Shin-rok is garnering significant attention for her compelling performance as Prosecutor Kang Young-ae in the MBC Friday-Saturday drama 'Fifty Percent' (오십프로). Across episodes 3 and 4, which aired on the 29th and 30th, her character deepened the tension by investigating a 10-year-old espionage and murder case alongside Kim Sang-ho. Beyond her screen success, Kim Shin-rok was also honored at the '62nd Baeksang Arts Awards with Gucci' gala dinner, where she received the Acting Award in the theater category. - Kim Shin-rok stars as Prosecutor Kang Young-ae in the MBC drama 'Fifty Percent', which reached a peak viewership rating of 6.1%. - She was officially recognized for her artistic excellence by winning the Acting Award in the theater category at the '62nd Baeksang Arts Awards with Gucci'. Q: Why is this trending? A: Kim Shin-rok is trending due to her dual success in receiving a prestigious acting award at the 62nd Baeksang Arts Awards and her gripping performance in the hit drama 'Fifty Percent'.